I've got lazy and didn't let you know the final result of my challenge. Remember I bet with a guy over the internet that I am going to get more second prizes than him using the same amount of money. He used $200 for a "Cash 5" game and didn't manage to get any second prize (4 numbers on the same row) for 200 draws in a row. Instead of using random numbers I used a few lottery systems and, as I let you know, I managed to catch 5 second prizes and the challenge was not over at the time. Now it's over (it stopped a few months ago) and meantime I managed to get another 3 second prize winners. So in total I've got 8 second prize winners compared to zero for the other guy. You can argue that I've got lucky once or twice but 8 times compare to nothing can't be a coincidence. If you don't believe me do the same thing, pick some random numbers or use some of the systems I presented on this site and see which one is going to get you more results.
The question you may ask is WHY lottery systems work? The answer it's easy: mathematics. Let's say I am choosing the 15 numbers system I show you in the other posts. If you want to play all the combinations possible you need to play 15*14*13*12*11/1*2*3*4*5 which is 3,003. You need to spend 3,003 dollars to play all these combinations. This is a huge amount of money. Of course if 5 numbers draw are among the 15 you chose you are guaranteed the jackpot. But if you miss a number you are going to get say 5-10 second prizes valued at around 100 each. But you can miss 2-3 or all 5 numbers and you lost a huge amount of money for only one draw. Instead of using 3,003 dollars to play all the combination possible out of 15 chosen numbers you can pick a lottery system that let's you play the same 15 numbers but in a reduced form using, 15, 27 or 118 dollars. The beauty of the lottery systems is that you use very little money compared with he original amount but the chances to get the second or the third prizes is not diminished considerable. How is this possible?
Assume you pick the first 15 numbers. If you play the full system you will have the following combinations;
1) 1-2-3-4-5
2) 1-2-3-4-6
3) 1-2-3-4-7
... and so on.
As you can see 1-2-3-4 is going to appear 11 times and the same goes for any other 4 numbers combination. When you are designing the system you can ask to computer that no given 4 number combination should appear more than once. So your reduced system is going to cost you 11 times less, yet the second prize is guaranteed. The systems I used for my challenge were cheaper, I spent only 27 dollars for 15 numbers system. These system actually guarantees only the third prize (3 numbers on the same line), yet I managed to get 4 numbers in a row (second prize) a few times. I also used a 10 numbers system that guarantees the second prize.
I know in principle how this systems are created but but I don't know enough programing so I can create them myself. If you know programing and you can explained in a language I understand a little bit (C or Perl) I'll be grateful.